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Conic sections — ACT practice questions

Practice 35 Conic sections questions in the app

What this topic is

Conic sections on the ACT Mathematics test cover the graphs and standard equations of circles, ellipses, parabolas, and hyperbolas in the coordinate plane.

A student must read an equation in standard form and pull out features such as the center, vertices, foci, directrices, and the slopes of a hyperbola's asymptotes. Items usually give a completed-square equation and ask which choice lists those features, the coordinates of the foci, or an equation of a parabola's directrix.

Common traps include swapping a and b, mixing horizontal and vertical openings, and treating a translated graph as if it were centered at the origin.

Sample questions

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Question 1Mid

Which of the following gives the center, vertices, and asymptote slopes of (x+1)216(y3)29=1\dfrac{(x+1)^2}{16}-\dfrac{(y-3)^2}{9}=1?

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Answer: D — Center (1,3)(-1,3); vertices (5,3)(-5,3) and (3,3)(3,3); slopes ±34\pm\dfrac34

The center is (1,3)(-1,3), and the positive xx term gives a horizontal transverse axis with a=4a=4. Thus, the vertices are (5,3)(-5,3) and (3,3)(3,3) and the asymptote slopes are ±b/a=±34\pm b/a=\pm\dfrac34.

Question 2Mid

The parabola y2=12xy^2=12x is graphed in the standard (x,y)(x,y) coordinate plane. Which of the following is an equation of its directrix?

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Answer: A — x=3x=-3

For y2=4pxy^2=4px with 4p=124p=12, p=3p=3. The parabola has vertex (0,0)(0,0) and opens right, so its directrix is the vertical line x=3x=-3.

Question 3Mid

In the standard (x,y)(x,y) coordinate plane, what are the coordinates of the foci of the hyperbola x216y29=1\dfrac{x^2}{16}-\dfrac{y^2}{9}=1?

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Answer: A — (±5,0)(\pm5,0)

For x216y29=1\dfrac{x^2}{16}-\dfrac{y^2}{9}=1, c2=a2+b2=16+9=25c^2=a^2+b^2=16+9=25, so c=5c=5. The transverse axis is horizontal, so the foci are (±5,0)(\pm5,0).

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Practice 35 Conic sections questions in the app

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